Question

Areas of two triangles are 25cm and 49cm² If the side of first triangle is 2.5 find the corresponding side of the triangle.​

Answer 1

Answer:

Altitude 2 = 2.88 cm

Step-by-step explanation:

Given : Area of two similar triangles is 25cm² and 36cm² . Altitude of first ∆ = 2.4cm.

We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding altitudes.

ar(∆1)ar(∆2) = (altitude 1/ altitude 2)²

25/36 = (2.4/altitude 2)²

On taking square root on both sides,

√25/36 =√(2.4/altitude 2)²

⅚ = 2.4/ altitude 2

5 × altitude 2 = 6 × 2.4

Altitude 2 = (6 × 2.4)/5

Altitude 2 = 14.4 /5 cm

Altitude 2 = 2.88 cm