Question

Arectangular classroom 90 m long and 75 m wide has a 15 m wide strip marked along its inner boundary . find the area of the strip.

Answer 1

Answer❀✿°᭄

Let Z be the number

Z = 13x + 11 where x is the quotient when Z is divided by 13

Z = 17y + 9 where y is the quotient when Z is divided by 17

13x + 11 = 17y + 9

13x + 2 = 17y since x and y are quotients they should be whole numbers . Since y has to be a whole number the left hand side should be multiple of 17

The least possible value of x satisfying the condition is 9 and y will be 7

The answer is 13*9 + 11 = 128 or it is 17*7 + 9 = 128

This is the least number possible. There will be multiple answers and will increase in multiples 17*13 = 221 like 349 , 570, etc

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Answer 2

Step-by-step explanation:

$\mathfrak{answer \: !}$

the length of the classroom is = 90 m

breadth = 75 m

the breadth of the strip is 15 m

so the area of the strip=

area of a rectangle is length×breadth

90×75 m = 6750 m

so the area of the strip =

please refer to the attachment to understand more

Area of the a part is = 90×15= 1350 m

area of the second part is 75-30=45m

so the area = 45×15 m = 675.

area of the c part = 90×15=1350

area of the d part = 45×15 m = 675 m

so the sum of all the area = 1350+1350+675+675= 4050 m²