Math, asked by dharmveersharma635, 4 months ago

Arectangular field 48 gom long and eds perimeters
perimeter is 310
then find its width.

Answers

Answered by usharawat12884

0

Perimeter of rectangle = 2(l+b)

310 = 2(48+b)

310 = 96 + 2b

310-96 = 2b

214 = 2b

214/2 = b

107 = b

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