Question

Arectangular vessel (22 cm x 18 cm x 14 cm) is filled with water. If the entire water is poured
into an empty cylindrical vessel of radius 6 cm, find the height of water in the cylindrical
vessels​

Answer 1

$\huge{\underline{\underline{\red{Answer}}}}$

$\mathbb{\boxed{\pink{GIVEN}}}$

• Measurement of the rectangular vessel=22cm×18cm×14cm

• Radius of cylindrical vessel = 6cm.

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$\Large{\underline{\underline{\red{SOLUTION}}}}$

The volume of the rectangular vessel is:

= length × breadth × height

= 22cm×18cm×14cm

$\bold{\boxed{\green{=22×18×14}{cm^{3}}}}$

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Volume of a cylindrical vessel is:

=$\pi {r}^{2} h$

Where r= radius and h= height.

Now as the the water is poured into the cylindrical vessel,

thus,

Volume of rectangular vessel = Volume of water in cylinder.

From this we can say,

$22 \times 18 \times 14 {cm}^{3} = \pi {r}^{2} h \\ \implies \: 22 \times 18 \times 14 = \frac{22}{7} \times 6 \times 6 \times h \\ \implies \: h = \frac{22 \times 18 \times 14 \times 7}{6 \times 6 \times 22}cm \\ \implies \: h = 7 \times 7cm \\ \implies \: h = 49cm$

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$\large{\boxed{\boxed{\red{Height=49cm}}}}$

Answer 2

Answer:

☆ ANSWER ☆

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GIVEN :

RECTANGULAR VESSEL

L = 22 CM

B = 18 CM

H = 14 CM

RADIUS OF CYLINDER = 6 CM

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TO FIND :

THE HEIGHT OF THE CYLINDER

PROOF :

$volume \: of \: vessel \: = 22 \times 18 \times 14 \\ = 5544 {cm}^{3}$

THE VOLUME OF THE VESSEL IS SAME AS THE CYLINDERICAL VESSEL.

THEREFORE ;

$vol \: of \: cylinder \: = 5544 \\ \pi {r}^{2} h = 5544 \\ 22 \div 7 \times 36 \times h = 5544 \\ h = 5544 \times 7 \div 36 \times 22 \\ h = 49 \: cm$

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