Question

Arectangularsheatofpaper10⅓cmlongand10¾cmwide.Find itsperimeter​

Answer 1

Answer:

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Answer 2

Answer:

Length of rectangular sheet = 10 + = all cm 102

Breadler of rectangular sheet = 25 m 3

Perimeter =

2x (l+b)

(21 + 25

3

[(21x5) + (26Y2)]] (21×3) +(25×2)

6

2x 113

= 2 ×

= 2x

12 & 3 are

co-primes]

= 113 = 374 cm

= 37 2/3.

Step-by-step explanation:

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