Arectangularsheatofpaper10⅓cmlongand10¾cmwide.Find itsperimeter
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Answered by
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Length of rectangular sheet = 10 + = all cm 102
Breadler of rectangular sheet = 25 m 3
Perimeter =
2x (l+b)
(21 + 25
3
[(21x5) + (26Y2)]] (21×3) +(25×2)
6
2x 113
= 2 ×
= 2x
12 & 3 are
co-primes]
= 113 = 374 cm
= 37 2/3.
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