Question

Arey sister has a resistance resistance of 106 ohms how many of these resistors should be connected in a parallel so that their combinations draw a current of 5 ampere from a 220 volt supply lines

Answer 1

i think the question is wrong as if u take it as 106 then u will get 2.409 resistors which is not possible.It should ideally be 176

For Resistors in Parallel,

1/R(total) = 1/R₁ + 1/R₂ + 1/Rₓ

From Ohm's Law 

V = IR

220 = (5)R

R = 44 Ω

Therefore

1/44 = No. of 176Ω Resistors * 1/176

Let no. of 176Ω Resistors be x

Then 1/44 = x/176

x = 4

Therefore, 4 resistors of 176Ω ( in parallel) are required to carry 5 A on a 220 V line.