Question

Argon gas at initial temperature 20 degree celsius is gas is expanded adiabatically 8 time to initial volume then find final temperature of a gas

Answer 1

Answer:

The final temperature of gas is  4.965°C

Explanation:

Initial temperature of argon ( T₁ ) = 20°C.

Let the initial volume of argon ( v₁ ) = V

The gas is expanded adiabatically,

Final volume of gas ( v₂ ) = 8 * V.

We have to find final temperature ( T₂ ) = ?

Now using the ideal gas equation for adiabatic expansion.

$\frac{T_{2} }{T_{1} } = ( \frac{v_{1} }{v_{2} } )^{\gamma -1}$

$\gamma= 1.67$  for argon.

$T_{2} = 20* ( \frac{1}{8} )^{1.67 - 1}$ = 4.965°C

Answer 2

Answer:

-200 degree Celsius or 73 kelvin

Explanation:

Put the value of temperature in kelvin when it comes to applying it in state equations. Proper calculations are in the image submitted with this answer.