Argument of -1-3i / 2+i
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-1-3i/2+i = (-1-3i)(2-i) /(2+i)(2-i) = -1-i
let z = -1-i =(-1,-1)
the point P(z) lies in the 3rd quadrant
tanα= I y I / I x I = 1 = tan45°
α=45° = Π/4
since the point lies on the 3rd quadrant
therefore, amp(z) = -π+α
=-π+π/4
=-3π/4
let z = -1-i =(-1,-1)
the point P(z) lies in the 3rd quadrant
tanα= I y I / I x I = 1 = tan45°
α=45° = Π/4
since the point lies on the 3rd quadrant
therefore, amp(z) = -π+α
=-π+π/4
=-3π/4
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