Question

Argument of {(1+i)/(1-1)} ​

Answer 1

Answer:

1 − i 1 + i = ( 1 − i ) ( 1 + i ) × ( 1 − i ) ( 1 − i ) 1−i1+i=(1−i)(1+i)×(1−i)(1−i)  =0 + i(-1) arg = tan-1  − 1 0 −10  = − π 2 −π2