Question

Argument of complex number -1 -i is?​

Answer 1

Answer:

Argument of (-1 -i) $= \dfrac{\pi }{4}$

Step-by-step explanation:

Given that-

Complex number (A) = (-1 - i)

Comparing with z = x + iy

We have,

x = -1 and y = -1

Argument of A =?

We know that-

$Argument \ of \ z = tan^{-1}[\frac{y}{x}]$

$Argument \ of \ A = tan^{-1}(\dfrac{-1}{-1})$

                           $= tan^{-1}(1)$

But tan(1) = $tan\dfrac{\pi }{4}$

So, argument of A is-

$A = tan^{-1}[tan\dfrac{\pi }{4} ]$

Argument of (-1 -i) $= \dfrac{\pi }{4}$

Answer 2

Answer:

-3pi/4

Step-by-step explanation:

cuz argument in 3rd quad. I'd defined as

theta= -(pi-alpha)

and here alpha is pi/4

Now calculate it if u r smart..‍♂️