Arhombus of side 15 cm has two angles of 120° each. Find the length of the diagonals.
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inΔAOD
sin30°=AO/AD
1/2=AO/20
AO=10cm
∴diagonal AC=2AO=20cm
now
cos30°=OD/AD
√3/2=OD/20
OD=10√3cm
∴diagonal BD=2OD=20√3cm
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