Math, asked by mpavithraveda, 8 months ago

Ari measured the density of quartz three Gmes: 2.49 g/cm3, 2.56 g/cm3, and 2.72 g/cm3. The accepted value
is 2.65 g/cm3. What is the percent error of Ari’s average measurement?
Answer to two (2) decimal places (the hundredths place).

Answers

Answered by harsni01
0

Answer:

The answer to your question is: 2.26%

Step-by-step explanation:

Data

densities    2.49 g/cm3,  2.56 g/cm3, 2.72 g/cm3

accepted value = 2.65 g/cm3

accepted value = 2.65 g/cm3Process

            mean = (2.49 + 2.56 + 2.72) / 3 = 7.77 / 3

            mean = (2.49 + 2.56 + 2.72) / 3 = 7.77 / 3                      = 2.59 g/cm3

% error = | approx. - exact| / exact x 100

% error =  | 2.59 - 2.65 | / 2.65 x 100

% error = | -0.06| / 2.65 x 100

% error = 0.06/2.65 x 100

% error = 2.26 %

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