Question

Arithematic mean of 7 observations was found to
be 32. If 1 more observation 48 was to be added
to the data what would be the new moon of the
data?​

Answer 1

Step-by-step explanation:

ANSWER

ANSWERn=7

ANSWERn=7x

ANSWERn=7xˉ

ANSWERn=7xˉ =32

ANSWERn=7xˉ =32Mean=

ANSWERn=7xˉ =32Mean= n

ANSWERn=7xˉ =32Mean= nsumofallterms

ANSWERn=7xˉ =32Mean= nsumofallterms

ANSWERn=7xˉ =32Mean= nsumofallterms .

ANSWERn=7xˉ =32Mean= nsumofallterms .x

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ =

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32=

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x ∑x=224.

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x ∑x=224.If one more observation is 48, then ∑x=224+48=72.

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x ∑x=224.If one more observation is 48, then ∑x=224+48=72.∴ New Mean=

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x ∑x=224.If one more observation is 48, then ∑x=224+48=72.∴ New Mean= 8

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x ∑x=224.If one more observation is 48, then ∑x=224+48=72.∴ New Mean= 8272

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x ∑x=224.If one more observation is 48, then ∑x=224+48=72.∴ New Mean= 8272

ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x ∑x=224.If one more observation is 48, then ∑x=224+48=72.∴ New Mean= 8272 =34

Answer 2

Answer:

n = 7

x = 32

mean = sum of all terms

n

x = x

n

32 = x

7

x = 224

If one more observation is 48, then x =

224+48=72

new mean = 272 = 34

8