Arithematic mean of 7 observations was found to
be 32. If 1 more observation 48 was to be added
to the data what would be the new moon of the
data?
Answers
Step-by-step explanation:
ANSWER
ANSWERn=7
ANSWERn=7x
ANSWERn=7xˉ
ANSWERn=7xˉ =32
ANSWERn=7xˉ =32Mean=
ANSWERn=7xˉ =32Mean= n
ANSWERn=7xˉ =32Mean= nsumofallterms
ANSWERn=7xˉ =32Mean= nsumofallterms
ANSWERn=7xˉ =32Mean= nsumofallterms .
ANSWERn=7xˉ =32Mean= nsumofallterms .x
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ =
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32=
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x ∑x=224.
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x ∑x=224.If one more observation is 48, then ∑x=224+48=72.
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x ∑x=224.If one more observation is 48, then ∑x=224+48=72.∴ New Mean=
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x ∑x=224.If one more observation is 48, then ∑x=224+48=72.∴ New Mean= 8
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x ∑x=224.If one more observation is 48, then ∑x=224+48=72.∴ New Mean= 8272
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x ∑x=224.If one more observation is 48, then ∑x=224+48=72.∴ New Mean= 8272
ANSWERn=7xˉ =32Mean= nsumofallterms .xˉ = n∑x 32= 7∑x ∑x=224.If one more observation is 48, then ∑x=224+48=72.∴ New Mean= 8272 =34
Answer:
n = 7
x = 32
mean = sum of all terms
n
x = x
n
32 = x
7
x = 224
If one more observation is 48, then x =
224+48=72
new mean = 272 = 34
8