Question

arithmatic progression ,if S5=35 and S4 =22 then find 5th term

Answer 1

Sum of five terms in ap is 35
Sum of four terms in ap is 23

Sum of five term =[n/2(2a+(n-1)d]
Sum of four term =[n/2(2a+(n-1)d]

35=5/2(2a+(5-1)d
14=2a+4d


22=4/2(2a+(n-1)d
11=2a+3d

14=2a+4d
11=2a+3d

D=3

By putting value d in eq we get

a=1

5 term of the ap is
a=a+(n-1)d
a=1+(5-1)3
a=1+12
a=13

Answer 2

Answer:13

Step-by-step explanation: Just subtract both equations you get T5