Math, asked by sachinn51, 11 months ago

Arithmetic and Geometric mean of roots of a Quadratic Equation are 8 and 5. Find the equation.​

Answers

Answered by GYMlover
1

Let the roots of the quadratic equation be aa and bb

It is given that the A.M of the roots =8=8 and their G.M.=5=5

We know that the A.M between aa and b=a+b2b=a+b2 and

G.M.=ab−−√=ab

⇒a+b2⇒a+b2=8=8 and ab−−√=5ab=5

⇒a+b=16⇒a+b=16 and ab=25ab=25

Since aa and bb are roots of the quadratic equation,

sum of the roots =a+b=16=a+b=16

Product of the roots =ab=25


sachinn51: where is the c complete answer
Answered by BraɪnlyRoмan
46

\huge \boxed{ \underline{ \underline{ \bf{Answer}}}}

Arithmetic mean of roots of Quadratic Equation = 8.

Geometric mean of roots of Quadratic Equation = 5.

Let, the roots of the quadratic equation be  \alpha and  \beta

A/Q,

For Arithmetic mean,

 \implies \:  \frac{ \alpha  \:  +  \:  \beta }{2}  =  \: 8

 \implies \:   \alpha  \:  +  \:  \beta  =  \: 16 \:  \:  \:

For Geometric mean,

 \implies \: \:  \sqrt{ \alpha  \beta }  \:  =  \: 5

Squaring, both sides

 \implies \:  { (\sqrt{ \alpha  \beta }) }^{2}  =  {5}^{2}

 \implies \:  \alpha  \beta  \:  =  \: 25 \:  \:  \:  \:  \:  \:  \:

We know, for Quadratic Equations

Sum of the zeroes(\alpha + \beta  ) = -b/a and

Product of zeroes ( \alpha \times \beta ) = c/a.

Hence, our required Quadratic Equation is

 \implies \:  {x}^{2}   - ( \alpha  +  \beta )x +  \alpha  \beta  = 0

 \boxed{ \sf{ \implies \:  {x}^{2}   - 16x + 25 = 0}}

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