Question

Arithmetic mean of 50 observations was 100.at the time of calculations tow observations 180 and 90 were omitted. find the corrected mean

Answer 1

Answer:

mean = 50

50*100=5000

adding Ommited observation

5000+270

5270

new mean 5270/100

new mean =52.7

Answer 2

Answer:

The corrected mean = 101.35

Step-by-step explanation:

Given,

Arithmetic mean of 50 observations  = 100

When the arithmetic mean is calculated two observations 180 and 90 were omitted

To find,

The corrected mean

Recall the formula

Arithmetic mean = $\frac{Sum \ of observations}{ Total \ Total \ number \ of \ observations}$ -------------------(1)

Solution:

Since the Arithmetic mean of 50 observations is 100,

From equation(1), the sum of observations = Arithmetic mean × Total number of observations

= 50 ×100

= 5000

When the omitted observations are included,

the sum of observations = 5000+180+90

= 5270

Now the total number of observations = 52

Hence, the corrected mean = $\frac{5270}{52}$ = 101.35

∴The corrected mean = 101.35

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