Question

Arithmetic mean of marks (out of 25) scored by )10 students was 15.one of the student, named karishma enquired the other 9 students and find the deviations from her marks are noted as -8,-6,-3,-1,0,2,3,4,6.find karishma's marks.

Answer 1

i hope it will be helpful to you
if it is so then mark it as brainliest

Answer 2

Marks of Karishma is 15.3

Solution:

Given that  

Arithmetic mean of marks (out of 25) scored by )10 students was 15

The deviations from karisma’s marks of other 9 students are noted as -8,-6,-3,-1,0,2,3,4,6.

Need to find karishma’s marks

Let assume mark of karisma = x

So marks of each student = marks of karishma + deviation of their marks from karisma mark  

So marks of remaining 9 students will be x – 8, x – 6 , x – 3 , x – 1 , x – 0 , x +2 , x + 3 , x + 4 , x + 6  

So total mark of 10 students = marks of karishma + marks of remaining 9 students

total mark of 10 students = x + x – 8+ x – 6 + x – 3 + x – 1 + x – 0 + x +2 + x + 3 + x + 4 + x + 6  

total mark of 10 students = 10x - 3

Number of students = 10

$\text{ Arithmetic mean of 10 students } =\frac{\text { total marks of 10 students }}{\text { number of students }}$

$\begin{aligned}&\Rightarrow 15=\frac{10 x-3}{10}\\\\&\Rightarrow 150+3=10 x\\\\&\Rightarrow 153=10 x\\\\&\Rightarrow x=\frac{153}{10}=15.3\end{aligned}$

Hence marks of Karishma = x = 15.3

Learn more about arithmetic mean

The arithmetic mean of the marks scored by students of a class is 58.20% of them secured a mean score of 60. the mean score of another 30% if the students was 40. the mean score of the remaining students is​

https://brainly.in/question/11874843

The number of students in four classes A, B, C, D and their respective mean marks obtained by each of the class are given below:

Class A Class B Class C Class D

Number of students 10 40 30 20

Arithmetic mean 20 30 50 15

The combined mean of the marks of four classes together will be:

https://brainly.in/question/4886531