Arithmetic mean of three numbers is 26. If two numbers are 24 and 33, what is the third number?
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Answer:
Let the numbers be:
a, b, c
Then:
(a+b+c)/3 = 23
==> a+ b + c = 69 .......(1)
But we know that:
b = a+ 6
==> a = b-6 .........(2)
also:
b+c = 54.........(3)
Now let us substitute (2) and (3) in (1):
a+ b + c = 69
(b-6) + 54 = 69
==> b = 69 - 54 + 6 = 21
==> b= 21
==> a = b-6 = 21-6 = 15
==> a= 15
==> b+c = 54
==> c = 54- 21 = 54- 21 = 33
==> c= 33
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