Question

ARITHMETIC PROGRESSION
Find a and d
1- 2, 5/2, 3, 7/2.…
2- ―1.2, ―3.2, ―5.2, ―7.2.....
3- –10, ―6, ―2, 2.....
4– 0, ―4, ―8, ―12....
5- ―1/2, ―1/2, ―1/2, ―1/2....
6- 1, 25, 49, 73....
7- a, a2, a3 ,4a....

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Answer 1

Arithmetic progression.

Find (a) and (d)

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a => First value in Ap series.

d => a2 - A1

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✨ SOLUTION ✨

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(1)

$1.) \: \: \boxed {a = > ( - 2)} \\ \\ d = > a2 - a1 \\ \\ d = > \frac{5}{2} - ( - 2) \\ \\ d = > \frac{5}{2} + \frac{2}{1} \\ \\ d = > \frac{5 + 4}{2} \\ \\ \boxed{ d = > \frac{9}{2} }$

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(2)-1.2,-3.2,-5.2.......

$2. \: \boxed{a = > - 1.2} \\ \\ d = > a2 - a1 \\ \\ d = > - 3.2 - ( - 1.2) \\ \\ d = > - 3.2 + 1.2 \\ \\ \boxed{d = > - 2}$

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(3)-10,-6,-2......

$3. \: \boxed{a = > - 10} \\ \\ d = > a2 - a1 \\ \\ d = > - 6 - ( - 10) \\ \\ d = > - 6 + 10 \\ \\ \boxed{ d = > 4}$

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(4)0,-4,-8,-12

$4.. \boxed{a = > 0} \\ \\ d = > a2 - a1 \\ \\ d = > - 4 - 0 \\ \\ \boxed{ d = > - 4}$

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(5)-1/2,-1/2,-1/2,.....

$5.. \boxed{a = > \frac{ - 1}{2} } \\ \\ d = a2 - a1 \\ \\ d = > \frac{ - 1}{2} - \frac{ - 1}{2} \\ \\ d = > \frac{ - 1}{2} + \frac{ 1}{2} \\ \\ \: \boxed{d = > 0}$

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Hope it's helps you ☺️

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