Question

arithmetic progression problem plz solve with solution

Answer 1

First !

a = -14 , d = -6-(-14) : -6+14= 8

Therefore n = 35 .. (Given in qstn )

Formula :-

N/2[2a+(n-1)d]

35/2 [ 2(-14) + 34(8) ]

35/2 [ -28 + 272 ]

35/2 [ 244 ]

On simplifying 244/2 we get :-

35 * 122 !!

Therefore the sum of first 35 terms of the given AP is :-

4,270 ..

Hope it helps you ..
Thank you ...
By Your caring friend ...

Answer 2

hope it helps you...and pls mark this as the brainliest


option 2 is the right one