arithmetic progression problem plz solve with solution
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2
First !
a = -14 , d = -6-(-14) : -6+14= 8
Therefore n = 35 .. (Given in qstn )
Formula :-
N/2[2a+(n-1)d]
35/2 [ 2(-14) + 34(8) ]
35/2 [ -28 + 272 ]
35/2 [ 244 ]
On simplifying 244/2 we get :-
35 * 122 !!
Therefore the sum of first 35 terms of the given AP is :-
4,270 ..
Hope it helps you ..
Thank you ...
By Your caring friend ...
a = -14 , d = -6-(-14) : -6+14= 8
Therefore n = 35 .. (Given in qstn )
Formula :-
N/2[2a+(n-1)d]
35/2 [ 2(-14) + 34(8) ]
35/2 [ -28 + 272 ]
35/2 [ 244 ]
On simplifying 244/2 we get :-
35 * 122 !!
Therefore the sum of first 35 terms of the given AP is :-
4,270 ..
Hope it helps you ..
Thank you ...
By Your caring friend ...
thirudeepak2003:
The answer is option two !
Pls now mark me as the brainliest answer my friend !!!
Answered by
0
hope it helps you...and pls mark this as the brainliest
option 2 is the right one
option 2 is the right one
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Hey rosh !!
The pic cld hv been clear to get a brainliest answer
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