Arithmetic Progression ques
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nth term of any AP is given by S(n)-S(n-1)
so, S(n)=3n²+2n
Hence nth term=3n²+2n-[3(n-1)²+2(n-1)]
=6n-3+2=6n-1.
so, S(n)=3n²+2n
Hence nth term=3n²+2n-[3(n-1)²+2(n-1)]
=6n-3+2=6n-1.
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