Arithmetic Progressions
Attachments:
Answers
Answered by
2
12. a=3,d=2
Step-by-step explanation:
7. 7th term of an AP is zero
that means a+6d=0
now to prove 25th term is twice the 16th term
T25= a+24d
= a+6d+18d
=18d.....(as a+6d=0).....eq1
T16 = a+15d
= a+6d+9d
=9d......eq2
from eq1 and 2
T25=2T16
hence proved
10. done already(hope u liked the solution)
12. T4=3a...1
T7-2T3=1....2
from eq1
a+3d=3a
3d=2a.....3
from eq2
(a+6d)-2(a+2d)=1
a+6d-2a-4d=1
-a+2d=1
substituting eq3
-3d/2+2d=1
1/2d=1
d=2
substituting d=2 in eq3
a=3
hope it helps u
Similar questions