Question

ARITHMETIC
Q: A woman buys chickoos at Rs.25 a dozen and an equal number at Rs.30 a score. She sells
them at Rs.36 a score and thus makes a profit of Rs.10. How many chickoos did she buy?​

Answer 1

Answer:

12

Step-by-step explanation:

Answer 2

Given:

CP₁ = Rs. 25 a dozen

CP₂ = Rs. 30 a score

SP = Rs. 36 a score

Profit = Rs. 10

To find:

How many chickoos did she buy?​

Solution:

Let 2x number of chickoos.

x at Rs. 25 a dozen

x at Rs. 30 a score

1 dozen = 12 units

1 score = 20 units

$CP_t_o_t_a_l = (\frac{25}{12} * x) + (\frac{30}{20} * x )\\\\CP_t_o_t_a_l = (\frac{25}{12}x + \frac{3}{2}x )\\\\CP_t_o_t_a_l = (\frac{25x + 18x}{12} )\\\\CP_t_o_t_a_l = \frac{43}{12}x$

CP = 43x/12

$SP = \frac{36}{20}*2x\\\\SP = \frac{18}{5}x$

SP = 18x/5

Profit = SP - CP

$10 = \frac{18}{5}x - \frac{43}{12}x \\\\10 = \frac{216x - 215x}{60}$

10 × 60 = x

x = 600

Total chickoos bought = 2 × 600 = 1200

Therefore, she buys 1200 chickoos