Arithmetic sequence, the first term is –2, the fourth term is 16, and the nth term is 11 998. (a) find the common difference
d. (b) find the value of n.
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4th term is 16
1st term is -2
hence 4th term will be a + (4-1)d with their usual meanings
a = -2
16 = -2 + (3)d
d = 6
now nth term will be a + (n-1)d
11998 = -2 + (n-1)6
12000 = (n-1)6
n-1 = 2000
n = 2001
Hope you get it. :)
1st term is -2
hence 4th term will be a + (4-1)d with their usual meanings
a = -2
16 = -2 + (3)d
d = 6
now nth term will be a + (n-1)d
11998 = -2 + (n-1)6
12000 = (n-1)6
n-1 = 2000
n = 2001
Hope you get it. :)
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