Aritra and Nandy travel from X to Y and Y to X respectively at a uniform speed. If Aritra starts the journey at 6am while Nandy starts four hours later. They met at 2:10 pm. At what time will they reach their destinations, if both reach their destinations at the same time.(with step by step solution)
A 8 pm
B 7 pm
C 6 pm
D 7:30 pm
Answers
Answer:
A starts from X towards Y at 10 a.m. B starts from Y towards X at 11 a.m. If they reach their destinations at 2 p.m. and 5 p.m., respectively, at what time will they meet?
Let us assume that the distance between X and Y is x km.
It took A, 4 hours to complete journey from X towards Y and 6 hours for B to do the same from Y towards X.
So A is moving with a speed of x/4 kmph and B with x/6 kmph.
Here A will cover one-fourth of the distance from X to Y in one hour and B will cover one-fifth of the distance from Y to X in one hour.
That means by 11 a.m. A will cover x/4 km. So now within 3x/4 km they are going to meet each other. (as x-x/4 is the remaining distance A has to cover from 11 a.m. which is the starting time of B too)
From 11 a.m. A and B are going to spend sa
Let the distance between x and y is d. km.
Time taken by A in reaching from x to y = 10a.m. to 2p.m = 4 hrs.
Thus, speed of A = d/4.km/hr.
Time taken by B in reaching from y to x = 11 a.m to 5 p.m = 6 hrs.
Speed of B = d/6.km/hr.
Let they meet after t hours from 10 a.m. , accordingly :-
Distance covered by A in t hours. + distal covered by B in (t-1) hours = d.
(d/4)×t + (d/6)×(t-1) = d.
or, t/4+(t-1)/6= 1.
or, (5t-2)/12 = 1.
or, 5t - 2 = 12.
or, t = 14/5 hrs. Or 2 hours 48 minutes.
They will meet after 2 hrs 48 minutes from 10 a.m. i'e 12 : 48 p.m. Answer 8 pm
Answer: d
Step-by-step explanation: easy