Question

Arjun andhis son Arav werestanding ‘x’ m away from each other. They are equidistant(Y m)from a vertical cliff. Arjun burst a balloon and Arav heard the direct sound 0.5 seconds later and the echo after 2 seconds. If the speed of sound in air is 340m/s ,calculatei.the distance between Arjun and Arav ii.the distance between the cliff and Arjun

Answer 1

Answer:

hii please first be safe and stay at home okkk friend

Answer 2

Answer:

Given

v=340 m/s

t1 (direct)=0.5 sec

t2 (echo)=2 sec

Note:- here we are not adding it as the question didn't ask for 2sec after the first heard sound.

So,distance between arav and arjun= v x t1

                                                            = 340 x 0.5

                                                            = 170 m

Now for the distance between the cliff and Arjun= (v*t)/2

                                                                                 = (340 x 2)/2

                                                                                 = 340 m

Therefore, the distance between both of them is 170 m and distance between Arjun and the cliff is 340 m.

I hope this will help you

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