Arjun ate a number of chocolates on each of the 5 week days of a certain week. On Tuesday, he ate 2 more than on Monday and 8 less than on Wednesday. On Friday, he ate 4 more than on Thursday and 6 less than on Wednesday. The average number of chocolates he ate on the first three days and the last two days are in the ratio 4 : 3. Find the number of chocolates he ate on Thursday.
Answers
Given : Data about Arjun ate a number of chocolates on each of the 5 week days of a certain week
To find : the number of chocolates he ate on Thursday.
Solution:
Let say he ate on Monday = M
On Tuesday, he ate 2 more than on Monday
=> he ate on Tuesday = M + 2
On Tuesday he ate 8 less than on Wednesday
=> He ate on Wednesday = M + 2 + 8 = M + 10
On Friday, he ate 6 less than on Wednesday
=> He ate on Friday = M + 10 - 6 = M + 4
On Friday, he ate 4 more than on Thursday
=> He ate on Thursday = M + 4 - 4 = M
First three daya he ate = M + M + 2 + M + 10 = 3M + 12
Last two days het ate = M + M + 4 = 2M + 4
( 3M + 12 ) : (2M + 4) = 4 : 3
=> ( 3M + 12 ) / (2M + 4) = 4/3
=> 9M + 36 = 8M + 16
=> M = - 20
Hence mistake in data as chocolate ate can not be - ve
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Answer:
4
Step-by-step explanation:
in amitnrw's answer(the first soln here for the question), there's a slight mistake
it should be
3M+12/3:2M+4/2=4:3
=> M+4/M+2=4/3
=>M=4