Math, asked by slakshya946, 1 year ago

Arjun bought rice at rupees 1024 per quintal and sold it rupees 1100 per quintal if he made a profit of rupees 400 how many quintals did he buy and sells?

Answers

Answered by Anonymous
0
GMore than 5,,....

the profit for each is 76
76*5=380

now just find for 20 rs how much he want to sell

mark brainliest



as u requested


\begin{lgathered}let \: total \: number \: of \: quintals \: of \: rice \: bought \: be \: (x) \\ total \: expenditure \: = (1024)(x)rs \\ money \: recieved \: after \: selling \: \\ = (1100)(x)rs \\ now \: \\ profit \: = sp - cp \\ 400 = 1100x - 1024x \\ 400 = 76x \\ x = \frac{400}{76} = 5.2631 \: quintals \: (approx.)\end{lgathered}lettotalnumberofquintalsofriceboughtbe(x)totalexpenditure=(1024)(x)rsmoneyrecievedafterselling=(1100)(x)rsnowprofit=sp−cp400=1100x−1024x400=76xx=76400​=5.2631quintals

slakshya946: Bro please answered in details
Answered by MrJ109
0
HEY MATE. . . . HERE'S YOUR ANSWER. . . . . .
let \: total \: number \: of \: quintals \: of \: rice \: bought \: be \: (x) \\ total \: expenditure \:  = (1024)(x)rs \\ money \: recieved \: after \: selling \:  \\  = (1100)(x)rs \\ now \:  \\ profit \:  = sp - cp \\ 400 = 1100x - 1024x \\ 400 = 76x \\ x =  \frac{400}{76}  = 5.2631 \: quintals \: (approx.)
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