Math, asked by vvel237, 6 months ago

Arjun is twice as old as adhith .five years age Arjun's age was three times adhith's age

Answers

Answered by amuluibba
0

Answer:

Step-by-step explanation:

Let Arjun's present age be x

And Shriya's present age be y

Arjun is twice as old as shriya:-

x = 2y

Their ages before 5 years:-

Arjun's age = x-5

Shriya's age = y-5

Five years ago , his age was three times shriya's age

x-5 = 3(y-5)

x-5 = 3y-15

x-3y = -15+5

2y-3y = -10

-y = -10

y = 10

Therefore,x = 2(10) = 20

The present age of Arjun is 20 years and present age of Shreya is 10 years.

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Answered by saisha2492006
0

Let Adith's age be x,

Then Arjun's present age = 2x

5 years ago,

3(x−5)=(2x−5)

3x−15=2x−5

⇒x=10

Adith's present age is 10 years.

Arjun's present age is 2x= 2*10 = 20 years.

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