Math, asked by tanmayagarwal884, 9 months ago

Arjun is twice as old as adhith .five years age Arjun's age was three times adhith's age.find their greatest age

Answers

Answered by abhi569
14

Answer:

10 year and 20 year

Step-by-step explanation:

Let the present age of Adith be 'a'.

So the present age of Arjun should be twice of a or 2a.

Before 5 year:

Age of Adith = a - 5

Age of Arjun = 2a - 5

According to question:

= > Arjun's age = 3 * Adith's age

= > 2a - 5 = 3( a - 5 )

= > 2a - 5 = 3a - 15

= > 15 - 5 = 3a - 2a

= > 10 = a

Present age of:

Adith is a = 10 year

Arjun is 2a = 2(10) = 20 year

Answered by Anonymous
18

Answer:

Present age of Adith is 10 years and Arjun is 20 years.

Step-by-step explanation:

Let the present age of Adith be x.

Arjun is twice as old as Adhith.

Therefore, the present age of Arjun is 2x.

Five years age Arjun's age was three times Adhith's age.

Before 5 years

  • Age of Adith = (x - 5) years
  • Age of Arjun = (2x - 5) years

As per given condition,

→ 2x - 5 = 3(x - 5 )

→ 2x - 5 = 3x - 15

→ 15 - 5 = 3x - 2x

→ 10 = x

As, x is age of Adhith. So, present age of Adhith is 10 years.

Whereas age of Arjun is 2x. So, the present age of Arjun is 2(10) i.e. 20 years.

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