Math, asked by Anonymous, 7 months ago

Arjun is twice as old as adhith .five years age Arjun's age was three times adhith's age. find their ages.

Answers

Answered by monikasuresh2005
10

Arjun is 20 and Shriya is 10

Step-by-step explanation:

let age of Arjun be x

and age of adhith be x

then according to question x=2y−−−(1)

and five years ago

x−5=3(y−5)

x−5=3y−15

x−3y+10=0−−−(2)

using eq(1)

2y−3y+10=0

y=10

and x=20

∴ age of Arjun is 20 and age of Shriya is 10

hope this help u (^_^)

Answered by Anonymous
18

Present age of Adith is 10 years and Arjun is 20 years.

Step-by-step explanation:

Let the present age of Adith be x.

Arjun is twice as old as Adhith.

Therefore, the present age of Arjun is 2x.

Five years age Arjun's age was three times Adhith's age.

Before 5 years:

Age of Adith = (x - 5) years

Age of Arjun = (2x - 5) years

As per given condition,

→ 2x - 5 = 3(x - 5 )

→ 2x - 5 = 3x - 15

→ 15 - 5 = 3x - 2x

→ 10 = x

As, x is age of Adhith. So, present age of Adhith is 10 years.

Whereas age of Arjun is 2x. So, the present age of Arjun is 2(10) i.e. 20 years.

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