Question

Arjun is twice as old as Ankita. Five years ago his qge was three times Ankita's age. Find their present ages.​

Answer 1

Answer:

Hi there.. Here's the answer for your question..

Step-by-step explanation:

Let Arjun be designated as A

Let Shriya be designated as S.

A is twice as old as S

Let S be x years old currently.

Therefore A is 2(x) years old currently.

5 years ago S was ( x - 5 ) years old

5 years ago A was (2(x) - 5) years old

5 years ago A was three times S' age.

That is, 5 years ago, ( 2x - 5 ) = 3( x - 5 )

or

2x - 5 = 3x - 15 so

3x - 2x = -5 + 15 or

x = 10

I stated that S' Current age was x years old. We have now identified x as 10 years old.

A is therefore identified as 2x years old or 20 years old.

Therefore currently Arjun and Shryia are 20 and 10 years old respectively.

PB

PP Note that 5 years ago A was 15 and S was 5, so A was three times S' age.

Hope it helps you....

If any doubt ask me. .

Thankyou...

Answer 2

Answer:

ARJUN IS 20 YEARS OLD AND ANKITA IS 10 YEARS OLD

Step-by-step explanation:

let age of Arjun be

′

x

′

and age of Ankita be

′

y

′

then according to question x=2y−−−(1)

and five years ago

x−5=3(y−5)

x−5=3y−15

x−3y+10=0−−−(2)

using eq(1)

2y−3y+10=0

y=10

and x=20

∴ age of Arjun is 20 and age of Ankita is 10