Question

Arjun is twice as old as Neha. Five years ago his age was three times Neha's age. Find their present ages.​

Answer 1

Answer:

• The present age of Neha = 10 yrs.
• The present age of Arjun = 20 yrs.

Step-by-step explanation:

Given,

• Arjun is twice as old as Neha.
• Five years ago his age was three times Neha's age.

To Find,

• Their present ages.

Solution,

Let's,

• The present age of Neha = x

So,

• The present age of Arjun = 2x

Before 5 years,

• The age of Neha = x - 5

And

• The age of Arjun = 2x - 5

Arjun's Age = 3(Neha's age)

• → 2x - 5 = 3(x - 5)
• → 2x - 5 = 3x - 15
• → 15 - 5 = 3x - 2x
• → x = 10

The value of x is 10 yrs.

The present age of Neha = x

• The present age of Neha = 10 yrs.

The present age of Arjun = 2x

• The present age of Arjun = 20 yrs.

Required Answer,

• The present age of Neha = 10 yrs.
• The present age of Arjun = 20 yrs.

Answer 2

Given :-

• Arjun is twice old as Neha.
• Five years ago Arjun's age was three times of Neha's age.

To Find :-

• Present age of Neha and Arjun

Let :-

• Neha's age be x
• And, Arjun's age be 2x

So :-

• Neha's age 5 years ago = x - 5
• And Arjun's age five years ago = 2x- 5

Solution :-

Five years ago, Arjun's age was thrice Neha's age, so,

$\longrightarrow \sf \: 2x - 5 = 3(x - 5) \: \: \\ \longrightarrow \: \sf2x - 5 =3x - 15 \: \: \: \: \\ \longrightarrow \: \sf 3x - 2x = - 15 + 5 \\ \longrightarrow \: \sf \: x = 10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf \therefore\red {Neha's \: age = x = 10} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf \orange {Arjun's\: age = 2x = 10 \times 2 = 20}$