Question

Arjun is twice as old as Shreya. 5 years ago his age was 4 times Shreya's
age. Find their present ages.

Answer 1

Answer:

Let Arjun be designated as A

Let Shriya be designated as S.

A is twice as old as S

Let S be x years old currently.

Therefore A is 2(x) years old currently.

5 years ago S was ( x - 5 ) years old

5 years ago A was (2(x) - 5) years old

5 years ago A was three times S' age.

That is, 5 years ago, ( 2x - 5 ) = 3( x - 5 )

or

2x - 5 = 3x - 15 so

3x - 2x = -5 + 15 or

x = 10

I stated that S' Current age was x years old. We have now identified x as 10 years old.

A is therefore identified as 2x years old or 20 years old.

Step-by-step explanation:

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