Question

Arjun is twice as old as Shriya.5 years ago he was three times Shriya age. Find their present ages

Answer 1

${\large{\bf{\red{\underline{\underline{Given :}}}}}}$

• Age of Arjun in present = x
• Age of shreya in present = y

${\large{\bf{\blue{\underline{\underline{To Find:}}}}}}$

• Find his present age .

${\large{\bf{\orange{\underline{\underline{Solution :}}}}}}$

Now,

• Age of Arjun now = x
• Age of Shreya now = y

• Age of Arjun before 5 years = x - 5
• Age of Shreya before 5 years = y - 5

Than,

${\mapsto{\bf{X - 5 = 3(y - 5)}}}$

${\mapsto{\bf{X - 5 = 3x - 15}}}$

${\mapsto{\bf{X - 3y = -15 + 5}}}$

${\mapsto{\bf{2y - 3y = - 10}}}$

${\mapsto{\bf{{\cancel-y ={\cancel - 10}}}}}$

${\blue{\dashrightarrow{\red{\boxed{\bf{Y = 10}}}}}}$

So,

${\red{\mapsto{\green{\bf{Arjun = X = 2(x) = 2 × 10 = 20 \: years}}}}}$

${\red{\mapsto{\green{\bf{Shreya = Y = 1 × 10 = 10 \: years }}}}}$

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