Question

Arjun is twice as old as shriya. 5 years ago his age was 3 times shriya's age. Find the present age

Answer 1

Answer:

let shriya age=x

arjun age=2x

according to question

3(x-5)=(2x -5)

3x-15=2x -5

x=10

so shriya age=10

arjun=20

Answer 2

solution:

$\footnotesize\texttt{Let us take shriya's age be x years. }$

$\footnotesize\texttt{then arjun's present age would be 2x years.}$

$\footnotesize\texttt{shriya's age five years ago was (x-5) years. }$

$\footnotesize\texttt{arjun's age five years ago was (2x-5) years. }$

$\footnotesize\texttt{it is given that arjun's age five.}$

$\footnotesize\textsf{ year ago was three times shriya's age.}$

Thus,

➠$\small\mathtt{2x-5=3(x-5) }$

➠$\small\mathtt{2x-5=3x-15 }$

➠$\small\mathtt{15-5=3x-2x }$

➠$\small\mathtt{10= x }$

so,shriya's present age =x =10 Years .

therefore, arjun's present age =2x=2×10=20 years.