Question

Arjun is twice as old as shriya . five years ago his age was three times shriya’s age. Find their present ages

Answer 1

let Arjun be denoted by A, and Shriya be denoted by S.

Now according to the first statement
A = 2S  [eq. 1]

According to the second statement
A-5 = 3(S-5)  [eq. 2]

Solving the second equation, we get,
A-5 = 3S-15
A = 3S-10

putting the value of A in eq. 1, we get,
3S-10 = 2S
3S-2S = 10
S = 10
A = 2S
A = 2x10
A = 20

hence,
Age of Arjun is 20 years, and that of Shriya is 20 years.

Answer 2

solution:

$\footnotesize\texttt{Let us take shriya's age be x years. }$

$\footnotesize\texttt{then arjun's present age would be 2x years.}$

$\footnotesize\texttt{shriya's age five years ago was (x-5) years. }$

$\footnotesize\texttt{arjun's age five years ago was (2x-5) years. }$

$\footnotesize\texttt{it is given that arjun's age five.}$

$\footnotesize\textsf{ year ago was three times shriya's age.}$

Thus,

➠$\small\mathtt{2x-5=3(x-5) }$

➠$\small\mathtt{2x-5=3x-15 }$

➠$\small\mathtt{15-5=3x-2x }$

➠$\small\mathtt{10= x }$

so,shriya's present age =x =10 Years .

therefore, arjun's present age =2x=2×10=20 years.