Math, asked by Anonymous, 1 year ago


Arjun is twice as old as Shriya. Five years ago his
age was three times
Shriya's age. Find their present ages.​

Answers

Answered by saanvi2678
0

Answer:

Let Arjun's age be x and shriya's age be y

A.T.Q.

x=2y

x-5=3 (y-5)

=>x-5=3y-15

=>2y-3y=-15+5

=>-y=-10

=>y=10

Now ,

x=2y

=>x=(2×10)

=>x=20

Therefore Arjun's age is 20 yrs and Shriya's age is 10 yrs.

Step-by-step explanation:

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Answered by Champion55
1

↦Solution : -

Let Present age of Shriya be = x years

Then , Present age of arjun will be = 2x years

After 5 years : -

Age of Shriya = (x-5) years

Age of Arjun = (2x - 5) years

It is given ,

Arjun's age 5 years ago was three times Shriya's age..

So ,

2x - 5 = 3 (x - 5)

2x - 5 = 3x - 15

15 - 5 = 3x - 2x

10 = x

Therefore , Value of x is 10 ..

Now ,

Present age of Shriya = x

10 years

Present age of arjun = 2(x)

2(10)

20 years

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