Math, asked by singhanita1590, 9 months ago

Arjun is twice as old as Shriya. Five years ago his age was three times
Shriya's age. Find their present ages.​

Answers

Answered by priyanujbd12345
3

Answer:

Step-by-step explanation:

Let the present age of Shriya be x

so , the present age of Arjun = 2x

Five years ago,

             Shriya age was = x - 5

and Arjun age was =  2x -5

A/Q

            2x - 5 = 3 ( x - 5)

            2x - 5 = 3x - 15

          2x - 3x = - 15 + 5

          - x    =  - 10 (minus sign will be neglected as both RHS and LHS has - sign)

   ∴  x = 10

So, Present age of Shriya = 10 yrs

and Present age of Arjun = 2 × 10

                                          = 20 yrs

Answered by VaishviTopiwala
1

Answer:

ARJUN AGE =20 YEARS

SHRIYA AGE = 10 YEARS

Step-by-step explanation:

Let Shriya 's age be x

therefore Arjun 's age = 2x years

5 years ago ,

Shriya 's age= (x-5) years

Arjun's age =(2x-5) years

given,

2x-5=3(x-5)

2x-3x = -15+5

-x= -10

therefore, x = 10

therefore, Shriya's present age =10 YEARS

ARJUN 's present age =2x

=2 x 10

= 20 YEARS

Similar questions