Question

Arjun is twice as old as Shriya.Five years ago his age was three times shriya's age Find their present ages.

Answer 1

Let Shreya's age be x
Then Arjun's she will be 2x
5 years back there ages will be
2x -5 and x-5 and it tell that
2x-5=3(x-5)
Solving the equation we get the answer as x = 10

Answer 2

solution:

$\footnotesize\texttt{Let us take shriya's age be x years. }$

$\footnotesize\texttt{then arjun's present age would be 2x years.}$

$\footnotesize\texttt{shriya's age five years ago was (x-5) years. }$

$\footnotesize\texttt{arjun's age five years ago was (2x-5) years. }$

$\footnotesize\texttt{it is given that arjun's age five.}$

$\footnotesize\textsf{ year ago was three times shriya's age.}$

Thus,

➠$\small\mathtt{2x-5=3(x-5) }$

➠$\small\mathtt{2x-5=3x-15 }$

➠$\small\mathtt{15-5=3x-2x }$

➠$\small\mathtt{10= x }$

➠so,shriya's present age =x =10 Years .

➠therefore, arjun's present age =2x=2×10=20 years.