Math, asked by sub495, 7 months ago

Arjun is twice as old as Shriya. Five years ago his age was three times
Shriya’s age. Find their present ages.

Answers

Answered by jagdish101660
3

Answer:

Here is your answer Mate!

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Answered by ItzNavLoey
10

\huge\rm\underline{\underline{\purple{Qᴜᴇsᴛɪᴏɴ:-}}}

Arjun is twice as old as Shriya. Five years ago his age was three times Shriya's age. Find their present ages.

\huge\rm\underline{\underline{\blue{Aɴsᴡᴇʀ:-}}}

↬ Let us take Shriya's age to be x years.

↬ Then Arjun's present age would be 2x years.

↬ Shriya's age five years ago was (x - 5) years.

↬ Arjun's age five years ago was (2x - 5) years.

↬ It is given that Arjun's age five years ago was three times Shriya's age.

\sf{2x~-~5~=~3(x~-~5)}

\sf{2x~-~5~=~3x~-~15}

\sf{15~-~5~=~3x~-~2x}

\sf{10~=~x}

\rm\pink{❥~So,~Shriya's~present~age~=~x~=~10~years.}

\rm\red{❥~Therefore,~Arjun's~present~age~=~2x~=~2~×~10~=~20~years.}

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