Math, asked by eteteyuooo, 5 months ago

Arjun is twice as old as shriya. Five years ago his age was three times Shriya's age.


Proper answer needed!!​

Answers

Answered by SweetCharm
27

Correct question:

\tt\longrightarrow{} Arjun is twice as old as Shriya. Five years ago his age was three times Shriya's age. Find their present ages.

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Given:

  • Arjun is twice as old as Shriya.
  • Five years ago his age was three times Shriya's age.

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To find:

  • Their present ages.

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Solution:

★ Let us take Shriya's present age to be x years.

★ Then Arjun's present age would be 2x years.

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\star{\boxed{\sf{\orange{Shriya's\: age\: five\: years\: ago\: was (x - 5) years.}}}}

\star{\boxed{\sf{\purple{Arjun's\: age\: five\: years\: ago\: was (2x - 5) years.}}}}

※ It is given that Arjun's age five years ago was three times Shriya's age.

Thus,

\large{\tt{\longmapsto{2x - 5 = 3(x - 5)}}}

\large{\tt{\longmapsto{2x - 5 = 3x - 15}}}

\large{\tt{\longmapsto{15 - 5 = 3x - 2x}}}

\boxed{\large{\tt{\longmapsto{\red{10 = x}}}}}

So,

Shriya's present age:-

\large{\tt{\longmapsto{x = 10~ years.}}}

Therefore,

Arjun's present age:-

\large{\tt{\longmapsto{2x = 2 × 10 = 20~years.}}}

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Answered by gurvanshdeep1234
3

ANSWER FOR YOUR QUESTION:-

Let Shriya's present age is x years. Then, Arjun's present age will be 2x years.

Five years ago,

3(x−5)=(2x−5)

3x−15=2x−5⇒x=10

Shriya's present age is 10 years.

Arjun's present age is 20 years.

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