Question

Arjun is twice as old as Shriya. Five

years ago his age was three times

Shriya’s age. Find their present ages.​

Answer 1

Answer:

2x

is the write answer I think

Answer 2

Solution

Let Shriya's present age be x years and Arjun's present age be 2x years.

Five years ago,

Shriya's age = (x - 5)years

Arjun's age = (2x - 5)years

Now,

Given that,

Five years ago Arjun's age = 3 × Five years ago Shriya's age.

$:\implies\sf{2x - 5=3(x-5)}$

$:\implies\sf{2x-5=3x-15}$

$:\implies\sf{2x - 5 + 15=3x}$

$:\implies\sf{2x+10=3x}$

$:\implies\sf{3x=2x+10}$

$:\implies\sf{3x-2x=10}$

$:\implies{\boxed{\frak{\pink{2x =10}}}}$

Therefore,

Shriya's present age = x = 10 years and

Arjun's present age = 2x = 2 × 10 = 20

years!