Question

Arjun is twice as old as Shriya. Five years ago his age was three times
Shriya's age. Find their present ages.

Note:
- Need Full Explanation
- Don't Spam! ​

Answer 1

Answer:

10,20

five years ago age

10-5=5

and 20-5=15

Step-by-step explanation:

let 5 years ago

age of shriya is=X

then age of Arjun is=2X

and

present time shriya's age=X+5

and age of Arjun is=2X+5

as

2X+5=3(X+5)

2X+5=3X+15

-x=10

as age is not be negatively

so X=10

therefore age of shriya=10

and age of Arjun=2X

=2*10

=20

Answer 2

Question

Arjun is twice as old as Shriya. Five years ago his age was three times Shriya's age. Find their present ages.

Solution

Let Shriya's present age be x years and Arjun's present age be 2x years.

Five years ago,

Shriya's age = (x - 5)years

Arjun's age = (2x - 5)years

Now,

Given that,

Five years ago Arjun's age = 3 × Five years ago Shriya's age.

$:\implies\sf{2x - 5=3(x-5)}$

$:\implies\sf{2x-5=3x-15}$

$:\implies\sf{2x - 5 + 15=3x}$

$:\implies\sf{2x+10=3x}$

$:\implies\sf{3x=2x+10}$

$:\implies\sf{3x-2x=10}$

$:\implies{\boxed{\frak{\pink{2x =10}}}}$

Therefore,

Shriya's present age = x = 10 years and Arjun's present age = 2x = 2 × 10 = 20 years!