Math, asked by gamingmihir529, 5 hours ago

Arjun is twice as old as Shriya. Five years ago his age was three times

Shriya's age. Find their present ages.​

Answers

Answered by Rajnish7809
1

Arjun is twice as old as Shriya five years ago his age was three times Shriya's age. Find their present ages.

STEP BY STEP Explanation

Let, the age of Arjun be the ‘x’ years.

The age of Shriya is the ‘y’ years.

Now, according to the question, the age of arjun twice when compared with the age of Shriya. This gives us the first relation and we obtain equation (1).

x = 2y … (1)

5 years ago,

The age of Arjun = x – 5.

The age of Shriya = y - 5.

According to the question, five years ago Arjun’s age was 3 times the age of Shriya. This gives us the second relation and we obtain equation (2).

x−5=3(y−5)x−5=3y−15x−3y+10=0...(2)

Putting the value of x from equation (1) in equation (2), we get

2y−3y+10=0y=10

Putting the value of y = 10 in equation (1), the value of x is,

x=2yx=2×10x=20

Hence, the present age of Arjun is 20 years and the present age of Shriya is 10 years.

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