Math, asked by hajerabanu11, 1 year ago

Arjun is twice as old as Shriya.Five years ago his age was three times Shriyas age.Find their present ages

Answers

Answered by simran206
22
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Let \: the \: present \: age \: of \: Arjun = x \: years \\ Let \: the \: present \: age \: of \: Sjriya = y \: years \\ \\ Given \: that, \: Arjun \: is \: twice \: as \: old \: as \: shriya \\ x = 2y \\ \\Let \: the \: age \: of \: Arjun \: after \: 5years= (x - 5) \\ Let \: the \: age \: of \: Shriya \: after \: 5 \: years \: = (y - 5) \\ \\ Now, \: Acc \: .to \: statement :\\ \: x = 2y \\ = > x - 5 = 3(y - 5) \\ \\ = > x - 5 = 3y - 15 \\ \\ = > 2y - 5 = 3y - 15 \\ \\ = > - y = - 15 + 5 \\ \\ = > y = 10 \\ \\
SO, The Present age of Arjun is 20 years
and The Present age of Shriya is 10 years....
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hajerabanu11: How did u get it print like
hajerabanu11: Can u plz tell me from where u got the answer plz
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Answered by BrainlySamaira
9

Answer:

\footnotesize\texttt{Let us take shriya's age be x years. }

\footnotesize\texttt{then arjun's present age would be 2x years.}

\footnotesize\texttt{shriya's age five years ago was (x-5) years. }

\footnotesize\texttt{arjun's age five years ago was (2x-5) years. }

\footnotesize\texttt{it is given that arjun's age five.}

\footnotesize\textsf{ year ago was three times shriya's age.}

Thus,

\small\mathtt{2x-5=3(x-5) }

\small\mathtt{2x-5=3x-15 }

\small\mathtt{15-5=3x-2x }

\small\mathtt{10= x }

so,shriya's present age =x =10 Years .

so,shriya's present age =x =10 Years .therefore, arjun's present age =2x=2×10=20 years.

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