Math, asked by akshaya2715, 6 months ago

Arjun is twice as old as shriya.if five years ago his age was three times shriya's age, then find out arjun's present age... SPAM WILL BE REPORTED...

Answers

Answered by sukhmanibubbles
1

Answer:

Arjun's age= x

shriyas age= y

A.T.Q

x= 2y ---(1)

x-5 = 3(y-5) ---(2)

using one and 2

we get

y= 10

x= 2y therefore

x = 20

Answered by piyushsahu624
0

Answer:

Let, the age of Arjun be the ‘x’ years.

The age of Shriya is the ‘y’ years.

Now, according to the question, the age of arjun twice when compared with the age of Shriya. This gives us the first relation and we obtain equation (1).

x = 2y … (1)

5 years ago,

The age of Arjun = x – 5.

The age of Shriya = y - 5.

According to the question, five years ago Arjun’s age was 3 times the age of Shriya. This gives us the second relation and we obtain equation (2).

x−5=3(y−5)x−5=3y−15x−3y+10=0...(2)

Putting the value of x from equation (1) in equation (2), we get

2y−3y+10=0y=10

Putting the value of y = 10 in equation (1), the value of x is,

x=2yx=2×10x=20

Hence, the present age of Arjun is 20 years and the present age of Shriya is 10 years.

Step-by-step explanation:

Similar questions