Math, asked by opkalra1968, 10 months ago

Arjun is twice old as shriya fiveyears ago his age was three time's shriya's age. Find their present ages?

Answers

Answered by rahman786khalilu
0

Answer:

20,10

Step-by-step explanation:

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Answered by BrainlySamaira
16

Answer:

\footnotesize\texttt{Let us take shriya's age be x years. }

\footnotesize\texttt{then arjun's present age would be 2x years.}

\footnotesize\texttt{shriya's age five years ago was (x-5) years. }

\footnotesize\texttt{arjun's age five years ago was (2x-5) years. }

\footnotesize\texttt{it is given that arjun's age five.}

\footnotesize\textsf{ year ago was three times shriya's age.}

Thus,

\small\mathtt{2x-5=3(x-5) }

\small\mathtt{2x-5=3x-15 }

\small\mathtt{15-5=3x-2x }

\small\mathtt{10= x }

so,shriya's present age =x =10 Years .

therefore, arjun's present age =2x=2×10=20 years.

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