Math, asked by chitragavli76, 7 months ago

Arjun is twice old Sandhya five years ago his age was three times age of Sandhya find their present agee​

Answers

Answered by kuldeep20941
0

Step-by-step explanation:

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See The Attachment My Friend.....

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Answered by anishharsha
0

Answer:

Step-by-step explanation:

let Sandhya age be x.

   arjun age = 2x.

5 yrs ago:

       age of sandhya = x - 5

       age of arjun = 2x -15

       given : age of arjun is 3 times the age of sandhya

      3(age of sandhya) = age of arjun

       3(x - 5) = age of arjun

        3x - 15 = 2x - 5

        3x - 2x =  +15 - 5

          x = +10

 ∴present age of sandhya = x = 10 yrs

   present age of arjun = 2x = 2 × 10 = 20 yrs

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