Question

arjun lives at tumkur ajay at bangalore the two cities are 165 km apart arjuns initial speed is 2 km /hour he increases his speed by 2 km /hour . ajays speed is 4 km /hour he increases his speed by 2 km /hour after how many hours they will meet​

Answer 1

C.8 km/h

✔Ajay → (x+4) kmph.

A to B 60 km

Ravi → x kmph.

Let the speed of Ravi be x kmph;

Hence Ajay's speed = (x+4) kmph;

Distance covered by Ajay = 60 + 12 = 72 km;

Distance covered by Ravi = 60 - 12 = 48 km.

According to question,

72/(x+4) = 48/x

Or, 3/(x+4) = 2/x

3x = 2x+8

Or, x = 8 kmph.